I believe the Next Generation Computing is Software Defined Infrastructure on top of the robust physical infrastructure. You can ask me anything about enterprise infrastructure (virtualization, compute, storage, network) and we can discuss it deeply on this blog. Don't hesitate to contact me.
Tuesday, June 29, 2010
How to remove Cisco Nexus 1000V plugin
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The Cisco Nexus 1000V switch is a pure software implementation of a Cisco Nexus switch. It resides on a server and integrates with the hypervisor to deliver VN-Link virtual machine-aware network services. The Cisco Nexus 1000V switch takes advantage of the VMware vSphere vNetwork Distributed Switch framework to offer tightly integrated network services as part of both a server virtualization strategy and a broader data center virtualization strategy. In addition, the switch provides operations and management consistency with existing Cisco Nexus and Cisco Catalyst switches.
Here I would like to share how to remove Cisco Nexus 1000V Plugin
1. To view the extension key on the vCenter Server, open an Internet Browser, and enter the URL path http://
2. Authentication dialog box open, Enter the username and password and click OK
3. The Managed Object Browser (MOB) open the Service Instance page, in the value column of the Properties table, click Content
4. In the Value column of the Properties table, Click extensionManager OR you can open browser with URL http://localhost/mob/?moid=ExtensionManager
5. In the Methods table, click UnregisterExtension6. In the Value of the Parameters table, paste “Cisco_Nexus_1000V_1850055053″ and click Invoke Method.
Note: The actual value of “Cisco_Nexus_1000v_xxxxx” will wary. It should match the extension key from the Cisco_nexus_1000v_extension.xml file.
Enjoy!
Saturday, March 27, 2010
VMware ESX 4 can even virtualize itself
But what if you prefer to run ESX on ESX instead of Workstation?
Full article at:http://www.vcritical.com/2009/05/vmware-esx-4-can-even-virtualize-itself/
Tuesday, March 16, 2010
CFM to BTU formula
A BTU is a British thermal unit, which is the measure of energy to raise one CC of water one degree Celsius.
But you probably want to know about airflow in CFM (not water), and the amount of cooling (or heating) available in 1 cfm or airflow.
In Houston, we tend to cool things more than heat. We also try to drive moisture out of the air (dehumidify), but I won't discuss that now. The general equation to answer your question is like this: Qsens = cfm * 1.08 * (Tin - Tout) <-- "delta T"
You need to determine what your "delta T" is. For cooling a space to 75degF (23.89 degC), your dT is usually 20degF (-6.67 degC) with your supply air temperature (SA=55degF 12.78degC) and your return air temperature (RA=75degF 23.89 degC). This has been idealized and simplified. For cooling, 1cfm will do about 21.6btu/h of cooling. For heating, (SA=90/32.2, RA=68, 1cfm => 23.76btu/h)Citaton from: http://forum.onlineconversion.com/showthread.php?t=701
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CFM * 1.08 * tRise = Btu/hr
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General information follows.
That factor is based on standard conditions which are at sea level and A standard humidity level which i do not remember off hand. As altitude increases the factor decreases. At 2100 feet it is roughly 1.0.
The humidity also affects this number. Generally the greater the humidity the greater the factor.
1.08 Will be good enough for most applications though.
I'll give an example of the use:
Suppose the room temperature is 65.
We have a 1200 CFM blower. We measure an output temperature of 100.
100 - 65 = 35 tRise.
Now we have all the numbers to get our BUT/hr.
1200 * 1.08 * 35 = 45,360 btu/hr
This particular problem often compilments another, And that is how do we verify the CFM is as cited or measured with an anemometer.
Assuming we have electric heat and the temperature probe is not in line of site of the heating elements (to be sure we are not measuring the IR radiation) All you need to know is the power consumption. Either measure it with an amp meter. Or go with cited figure(not as accurate).
CFM = btu / (1.08 * tRise)
For reference: 1 kw/hr = 3412.14 btu
assume we have a 15kw heater and a tRise of 22
15kw * 3412.14 = 51182.12 btu
now we can solve for CFM
51182.12 / (1.08 * 22) = 2154.
In that example our result is 2,154 CFM.
If that conflicts with a suspected figure An investigation is required.
Keep in mind the factor is based on standard conditions. As a rule of thumb the result should be within 10% of the calculation. Anything out of this range is a trouble spot. Most likely to be a dirty air filter, or incorrect power factoring.
Monday, March 08, 2010
Monday, March 01, 2010
Tuesday, January 19, 2010
Storage fundamentals
http://www.vmdamentals.com/?p=266
Throughput part 2: RAID types and segment sizes
http://www.vmdamentals.com/?p=296
RAID 10 or RAID 5
I think that good choice depends on required performance, capacity, and data value stored on protected disks. RAID is just one type of protection and other protections should be used. Other data protections are:
- Backup
- Local Disk Replication (Volume Clones - Business Continous Volumes like i.e. EMC SnapView)
- Remote Disk Replications (EMC SAN Copy, EMC SRDF, IBM Metro Mirror, etc.)
So sometimes RAID 5 or 6 makes sense.
Thursday, January 14, 2010
Sunday, January 10, 2010
Tuesday, December 15, 2009
Thursday, December 10, 2009
Wednesday, December 09, 2009
Tuesday, December 08, 2009
EMC Celerra - Virtual Appliance
http://virtualgeek.typepad.com/virtual_geek/2009/04/new-celerra-vsa.html